Find the smallest no . that leaves 5 as remainder when divided by 36 & 54
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n = 5 + LCM(36,54)
n = 5 + LCM(9*2*2, 9*3*2)
n = 5 + 9*2*2*3 = 113
Hope it helped you...................................
n = 5 + LCM(9*2*2, 9*3*2)
n = 5 + 9*2*2*3 = 113
Hope it helped you...................................
rajeswar:
thanks for rating it the brainliest Devil53.......................
It's wrong
give the right answer than
pllease
sorry please
bro the answer is correct
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