Math, asked by ramamaheshwari1983, 9 months ago

find the smallest no. which leaves remainder 7 when divided by 35, 56 and 91 in each case. ​

Answers

Answered by k047
4

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

35=5×7

56=2

3

×7

91=7×13

LCM=2

3

×5×7×13=3640

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

Answered by pankaj202343
3

Answer:

now add 7 in that

Step-by-step explanation:

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