Question

Find the smallest no which when increased by 20 is exactly divisible by 90 and 144

Answer 1

The number equal to the L.C.M - 20 is the required number.

L. C. M of 90 , 144 .

90 = 2 * 3² * 5

144 = 3² * 2^4 .

L. C. M = 2^4 * 3² * 5 = 720 .

Required number = 720 - 20 = 700 .



the smallest no which when increased by 20 is exactly divisible by 90 and 144 is 700

Answer 2

Answer:

$\red{ \huge{ \boxed{700}}}$

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