find the smallest number by which 2560 must be multiplied so that the product a perfect cube
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first take l.c.m of 2560
2560=2×2×2×2×2×2×2×2×2×5
only'2×5' is unpaires so we mulriply this no by
2×5=10 ANS..
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2560=2×2×2×2×2×2×2×2×2×5
only'2×5' is unpaires so we mulriply this no by
2×5=10 ANS..
HOPE IT HELP
#BEBRAINLY
IF U LIKE MARK ME AS BRAINLIST
THANK U
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