Question

find the smallest number by which 3993 must be devided so that it become perfect cube​

Answer 1

Answer:

the smallest number is 3. 3993÷3=1331 which is a cube of 11

Answer 2

First, let us prime factorise the given number

3993 = 3×11×11×11

Check for numbers in triplets. We find that only 11 is occuring as a triplet. Hence we must eliminate the three.

So if we divide 3993 by 3, we'll get a perfect cube, that is 1331 (11³)

So, the answer is 3