Question

find the smallest number by which 53240 must be divided to get a perfect cube

Answer 1

$5324 0= {2}^{3} \times 5 \times {11}^{3 }$
to make it perfect cube ,
it must be divided by 2^3×5 =40

therefore 40

Answer 2

Step-by-step explanation:

Solution: 53240 = 2×2×2×11×11×11×5

The prime factor 5 does not appear in a group of three. So, 53240 is not a perfect cube. In the factorisation 5 appears only one time. If we divided the number by 5, then the prime factorisation of the quotient will not contain 5.

So,

53240÷5 = 2×2×2×11×11×11

Hence the smallest number by which 53240 should be divided to make it a perfect cube is 5.

The perfect cube in that case is=10648.