FIND THE SMALLEST NUMBER BY WHICH 8788 BE DIVIDED SO THAT it is PERFECT CUBE ?
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For a given number x we define cube
of x = x × x × x , denoted by x^3.
A given Natural number is a perfect
Cube if it can be expressed as the
product of triplets of equal factors.
Now ,
Write given number as product of
prime .
8788 = 2 × 4394
= 2 × 2 × 2197
= 2 × 2 × 13 × 169
= 2 × 2 × 13 × 13 × 13
= 2 × 2 × ( 13 × 13 × 13 )
Here we have only triplet of equal
factors i.e 13
To make 8788 into perfect Cube we
have multiply with 2.
Now ,
2 × 8788 = ( 2 × 2 × 2 ) × ( 13 × 13 × 13 )
17576 = ( 2 × 13 )^3 = ( 26 )^3 perfect
Cube
of x = x × x × x , denoted by x^3.
A given Natural number is a perfect
Cube if it can be expressed as the
product of triplets of equal factors.
Now ,
Write given number as product of
prime .
8788 = 2 × 4394
= 2 × 2 × 2197
= 2 × 2 × 13 × 169
= 2 × 2 × 13 × 13 × 13
= 2 × 2 × ( 13 × 13 × 13 )
Here we have only triplet of equal
factors i.e 13
To make 8788 into perfect Cube we
have multiply with 2.
Now ,
2 × 8788 = ( 2 × 2 × 2 ) × ( 13 × 13 × 13 )
17576 = ( 2 × 13 )^3 = ( 26 )^3 perfect
Cube
brainyperson:
nice explained
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