Find the smallest number by which 891/3500
must be multiplied to make it a terminating decimal.
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Answer:
:- For the no. to have a terminating decimal ,
the denominator has to be in the form of
{2}^{n} \: \times \: \: {5}^{n } \: or \: {10}^{n}2n×5nor10n
But in the question:-
\frac{891}{3500} = \frac{ {9}^{2} \times 11} { {7}^{1} \times {5}^{1 } \times {10}^{3} }3500891=71×51×10392×11
Hence, there is no such no. and this fraction does not have a terminating decimal.
Hope it helps, and please mark it as the brainliest...
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