Math, asked by abhinandaroychowdhur, 12 hours ago


Find the smallest number by which 891/3500
must be multiplied to make it a terminating decimal.​

Answers

Answered by paramdeepsingh061
0

Answer:

:- For the no. to have a terminating decimal ,

the denominator has to be in the form of

{2}^{n} \: \times \: \: {5}^{n } \: or \: {10}^{n}2n×5nor10n

But in the question:-

\frac{891}{3500} = \frac{ {9}^{2} \times 11} { {7}^{1} \times {5}^{1 } \times {10}^{3} }3500891=71×51×10392×11

Hence, there is no such no. and this fraction does not have a terminating decimal.

Hope it helps, and please mark it as the brainliest...

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