Find the smallest number by which 9408 must be divided so that the quotient is a perfect sqaure . Find the sqaure root of the quotient
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√9408 = √2*2*2*2*2*2*3*7*7
=2*2*2*7
3 is not in pairs.
Therefore, 3 must be divided by 9408 so that the quotient becomes a perfect square.
Square root= 9408/3=3136
Hope it help u if yes then plz mark it as brainlieast
=2*2*2*7
3 is not in pairs.
Therefore, 3 must be divided by 9408 so that the quotient becomes a perfect square.
Square root= 9408/3=3136
Hope it help u if yes then plz mark it as brainlieast
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