Question

find the smallest number by which each of following number must be multiplied to obtain perfect cube of 72​

Answer 1

Answer:

Step-by-step explanation:

We have 72 = 2 × 2 × 2 × 3 × 3

                 

                 Grouping the prime factors of 72 in triples, we are left over with 3 × 3.

                 ∴ 72 is not a perfect cube.

                 Now, [72] × 3 =[2 × 2 × 2 × 3 × 3] × 3

                 or 216 = 2 × 2 × 2 × 3 × 3 × 3

                 i.e. 216 is a perfect cube.

                 ∴ The smallest number required to multiply 72 to make it a perfect cube is 3.

Answer 2

${1}^{?} {113 \sqrt[1 = ..xxyyy]{?} }^{?}$