find the smallest number by which is divisible by each of the numbers 6, 9 and 15 and also do it by solution
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6 = 3*2
9 = 3*3
12 = 3*4
Therefore, the smallest no. by which the three no.s are divisible is 3.
9 = 3*3
12 = 3*4
Therefore, the smallest no. by which the three no.s are divisible is 3.
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