Find the smallest number by which the following must be divided to make it a perfect cube. And hence estimate the cube root of the perfect cube so obtained. (a) 725 (b) 550 (c) 1375 (d) 1824 please............ solve i. (Answers) (a) 4, 9 (b) 38, 8 (c) 44, 11 (d) 96, 12
Answers
Given :- Find the smallest number by which the following must be divided to make it a perfect cube. And hence estimate the cube root of the perfect cube so obtained. (a) 725 (b) 550 (c) 1375 (d) 1824
Solution :-
a) 725
Prime factors of 725 :-
→ 725 = 5 * 5 * 29
now, as we can see both 5 and 29 prime factors are 2 times and 1 time only .
in order to be a perfect cube a number must have pair of 3.
Therefore, we can conclude that, we have to remove all 5 and 29 .
Hence,
→ smallest Number by which divide to make a perfect cube is = 5 * 5 * 29 = 725 .
and, than ,
→ Result will be a perfect cube of = (725/725) = 1.
b) 550 .
Prime factors of 550 :-
→ 550 = 2 * 5 * 5 * 11
now, as we can see again none of the prime factors is in the pair of 3.
in order to be a perfect cube a number must have pair of 3.
Therefore, we can conclude that, we have to remove prime factors .
Hence,
→ smallest Number by which divide to make a perfect cube is = 550 .
and, than ,
→ Result will be a perfect cube of = (550/550) = 1.
c) 1375
Prime factors of 1375 :-
→ 1375 = 5 * 5 * 5 * 11
now, as we can see here 5 is in the pair of three. none of the prime factors is in the pair of 3.
Therefore, we can conclude that, we have to remove only 11 to make a perfect cube .
Hence,
→ smallest Number by which divide to make a perfect cube is = 11 .
and, than ,
→ Result will be a perfect cube of = (1375/11) = 125 = 5³ => 5 .
D) 1824 .
Prime factors of 1824 :-
→ 1824 = (2 * 2 * 2) * 2 * 2 * 3 * 19
as we can see here only 2 have one pair of 3.
Therefore, we need to remove rest prime factors to make a perfect cube .
Hence,
→ smallest Number by which divide to make a perfect cube is = 2 * 2 * 3 * 19 = 228 .
and, than ,
→ Result will be a perfect cube of = (1824/228) = 8 = 2³ => 2 .
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