find the smallest number divisible by 15,20,24,32,36
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The smallest no. divisible by any twoor more numbers is the L.C.M. of all those numbers. therefore, taking the LCM of 15,20,24,32,and 36.
2*2*2*2*2*3*3*5*5= 7200.
so 7200 is the required number.
2*2*2*2*2*3*3*5*5= 7200.
so 7200 is the required number.
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Hi friend
Here is your Answer
The smallest number divisible by 15,20,24,32,36 can be find out by taking their LCM
so
Prime factorize all the numbers.
15=3×5
20=2×2×5
24=2×2×2×3
32=2×2×2×2×2
36=2×2×3×3
Power of two in LCM
should be the highest power above of two
that is 5.
For 3 and 5 power is 2 and 1 respectively.
LCM=2^5× 3^2×5=1440
So the smallest number 1440 which is divisible by them
Hope it's helpful ✌✌
Here is your Answer
The smallest number divisible by 15,20,24,32,36 can be find out by taking their LCM
so
Prime factorize all the numbers.
15=3×5
20=2×2×5
24=2×2×2×3
32=2×2×2×2×2
36=2×2×3×3
Power of two in LCM
should be the highest power above of two
that is 5.
For 3 and 5 power is 2 and 1 respectively.
LCM=2^5× 3^2×5=1440
So the smallest number 1440 which is divisible by them
Hope it's helpful ✌✌
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