find the smallest number divisible by first 10 natural numbers
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The first 10 Natural numbers are 1,2,3,4,5,6,7,8,9,10
Find the LCM of 1 to 10
2×2×2×3×3×5×7=25202×2×2×3×3×5×7=2520
Hence the smallest number divisible by first 10 natural number is 2520
Answer : 2520
HERE IS UR ANSWER BUDDY
The first 10 Natural numbers are 1,2,3,4,5,6,7,8,9,10
Find the LCM of 1 to 10
2×2×2×3×3×5×7=25202×2×2×3×3×5×7=2520
Hence the smallest number divisible by first 10 natural number is 2520
Answer : 2520
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