Math, asked by dukedom1391, 1 year ago

Find the smallest number of 4 digits which is divisible by 18,24,32

Answers

Answered by kartik2507
4

we need to find LCM of 18, 24, 32

it is 288

therefore the number will be a multiple of 288

288×1=288

288×2=576

288×3=864

288×4=1152

first 4 digit number divisible by 18, 24, 32 is 1152

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Answered by snandy2005
0

Answer:

1008

Step-by-step explanation:

as it is written smallest 4 digit number  we have to find the L.C.M

the  L.C.M comes as = 72

THEN WE HAVE TO MULTIPLY 72 BY ANY NUMBER AND THE FIRST 4 DIGIT NUMBER IS THE SMALLEST WHICH IS DIVISIBLE BY 18,24,32

THE ANSWER : 72 X 14 = 1008

ANS: 1008

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