Question

Find the smallest number of 5 digits which exactly divisible by 16,25,30 and40.

Answer 1

LCM of 20 ,25 and 30 =300

Smallest 5 digit no. =10000

10000÷ 300 leaves the remainder 100

300 - 100 = 200

10000+200= 10200

Therefore, 10200 is the smallest 5 digit number divisible by 20 , 25 and 30

Answer 2

Lcm of 16,25,30and40
=6600

The smallest 5-digit no. = 10000

To find the no., we have to divide 10000 by 6600

6600)10000(1
6600
------------
3400
Therefore , the required no.
=10000+ (6600-3400)
=13200