find the smallest number of 5 digits which when divided by 20, 24, 35 and 45 leaves 5 as reminder. (note ans. is 10085)
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Answer:
5-digit no.=LCM of 20 25 35 45=2520
Remainder=5
Required no.= 2520-5
=2515
Smallest 5 digit no.=10000
Now,10000÷2515 =31
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