Find the smallest number of five digits that can be exactly divided by 60 90 and 80
Answers
Answered by
46
Heya Friend!!
Here's ur answer:-
*Firstly we find the LCM of 60,90 & 80
60:- 2 × 2 × 3 × 5
90:- 2 × 3 × 3 × 5
80:- 2 × 2 × 2 × 2 × 5
LCM= 720
*Smallest Five digit number = 10000
*Dividing this five digit number by 720.
we get,
720) 10000 ( 13
720
-_____
2800
2160
-_____
640
*To find the number
=> 10000 + ( 720 - 640 )
=> 10000 + 80
=> 10080
So, 10080 is the number of five digit & the required number!!
@Altaf
Here's ur answer:-
*Firstly we find the LCM of 60,90 & 80
60:- 2 × 2 × 3 × 5
90:- 2 × 3 × 3 × 5
80:- 2 × 2 × 2 × 2 × 5
LCM= 720
*Smallest Five digit number = 10000
*Dividing this five digit number by 720.
we get,
720) 10000 ( 13
720
-_____
2800
2160
-_____
640
*To find the number
=> 10000 + ( 720 - 640 )
=> 10000 + 80
=> 10080
So, 10080 is the number of five digit & the required number!!
@Altaf
Answered by
3
Answer:
first we need to find the lcm of the numbers-60,80,90
the lcm statement is- 2×5×2×3×2=720
to find the number -
we need to divide 720÷10000= quotient is 13 and the reminder is 640
= 10000+(720-640)
= 10000+80
- the final answer is 10080
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