Find the sum to n terms of the series 2 22 222
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Sn=a/2{2a+(n-1)d}
n/2{2×2+(nd-d)}
n/2(4nd-4d)
n÷2{4(nd-d)}
2n(nd-d)
n/2{2×2+(nd-d)}
n/2(4nd-4d)
n÷2{4(nd-d)}
2n(nd-d)
Answered by
10
Find the sum of n terms of series 2+22+222+..…... n terms.
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