Question

find the smallest number such that when it is divided by 28,38 and 48 leaves the remainders 18, 28 and 38 respectively

Answer 1

Since remainders are given
therefore remainder theorem can be used
x=28×a+18...........1
x=38×b+28...........2
x=48×c+38...........3
Equating 1 and 2 we can get relation between a and b ........4
equating 2 and 3 we can get relation between
b and c.......5
equating 1 and 3 we can get relation between a and c ......6
by solving 4 ,5 and 6 could get value of a,b and c.
by substituting we can get the value of x .

Regards,
HARISARAN G