find the smallest number that divides 44 55 and 220 leaving remainder 5
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Now according to the question , when 90 would be divided by 44, 55 & 220, it should leave a remainder 5. c) 225/220 has a Remainder =5 Thus the answer is 225.
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all the number leaves remainder 5
so, the questiont are----
44-5 = 39
55-5=50
220-5 =115
now breaking all the questionts into itf factors
39=3*13
50=5*5*2
115=5*23
so the smallest number that divides 44, 55 and 220 leaving remainder 5 in each case is 1
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