Question

Find the smallest number that is divisible by each of the numbers 7, 21 and 56. give a step by step explanation and please answer fastly

Answer 1

$\huge\mathfrak\purple{Solution:-}$

★ Answer:-

→ 7 is the smallest number that is divisible by 7, 21 and 56. (excluding the number 1).

★ Step-by-step explanation:-

→ We have,

• Factors of 7 :- 1 and 7

• Factors of 21 :- 1, 3, 7 and 21

• Factors of 56 :- 1, 2, 4, 7, 8, 14, 28 and 56

Therefore,

Looking at the factors of the given numbers, we can conclude that 7 is the smallest number that is divisible by 7, 21 and 56 excluding the number 1.

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I hope this helps! :)