Question

find the smallest number that must be added to 623 so that it becomes exactly divisible by 5​

Answer 1

Answer:

The answer is 2

Step-by-step explanation:

First divide it by 5 and whatever the remainder is add it. so after dividing the remainder is your answer.

Answer 2

Answer:

The required number is 2.

Step-by-step explanation:

The divisibility rule of the number 5:-

• If the digit on the units place (or the last digit) of any given number is 5 or 0, then such number is divisible by 5.

Step 1 of 1

Consider the given number as follows:

623

Notice that the units place digit (the last digit) of the number 623 is 3.

The number 623 exactly divisible by 5 only when the last digit becomes either 0 or 5.

Case1. Make the last digit 0.

Add 7 to the number 623.

⇒ 623 + 7 = 630

Clearly, the number 630 is exactly divisible by 5.

Case2. Make the last digit 5.

Add 2 to the number 623.

⇒ 623 + 2 = 625

Clearly, the number 625 is exactly divisible by 5.

Therefore, the number 2 is the smallest number that must be added to 623 to make it exactly divisible by 5.

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