Question

find the smallest number to be added or subtracted so that 11715 is divisible by 6 and 9

Answer 1

Answer:

First the LMC of 6 and 9 is 18.

Now divide, 11715 / 18.

The quotient is 650 and the remainder is 15.

So you need to subtract 15 or add 3 to 11715 to make it divisible by 6 and 9.

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Answer 2

Answer:

Step-by-step explanation:

First , we find the LCM of 6 and 9 i.e. 18

Then , we divide 11715 by 18 which gives us the quotient 650 and remainder 15

So, 15 must be divided to get 11700which is divisible by both 6and 9