Find the smallest number to which if 7be added, the number obtained be exactly divisible by 25, 45, 63, 84
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Answer:
Step-by-step explanation:
For that
First we have to find Least Common Multiple L.C.M. of 25,45,63,84 by the method of facrorisation
Hence we get LCM as 6300
Now this is the number which is divisible by all the numbers mentioned above
Now to get the desired answer we have to subtract 7 from it
So Answer= 6300-7 =6293
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