Math, asked by iqbalgahla50201, 2 months ago

Find the smallest number to which if 7be added, the number obtained be exactly divisible by 25, 45, 63, 84

Answers

Answered by chavanabhishek2596
2

Answer:

Step-by-step explanation:

For that

First we have to find Least Common Multiple L.C.M. of 25,45,63,84 by the method of facrorisation

Hence we get LCM as 6300

Now this is the number which is divisible by all the numbers mentioned above

Now to get the desired answer we have to subtract 7 from it

So Answer= 6300-7 =6293

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