Question

find the smallest number when diminished by 3 is divisible by 21 28 36 and 45. complete solution plz​

Answer 1

Answer:

Step-by-step explanation:

The prime factorization of 14,28,36,45 is:

Factors of 14 = 2 * 7

Factors of 28 = 2 * 2 * 7

Factors of 36 = 2 * 2 * 3 * 3

Factors of 45 = 3 * 3 * 5.

LCM(14,28,36,45) = 2 * 2 * 7 * 3 * 3 * 5

= > 1260.

Therefore, the smallest number = 1260 + 3  =1263.

Hope it helps!