find the smallest number when divided by 24 and 81 leave a remainder 5 in each case
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Answered by
19
Answer:
LCM of 24 and 81 = 108
108+5 =113
So, The smallest number divided by 24 and 81 which leaves reminder 5 in each case is 113.
Step-by-step explanation:
Answered by
0
Answer:
rdghrfhuyrddguu
Step-by-step explanation:
ttyrryu
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