Math, asked by kumarsudip343parra5, 1 year ago

Find the smallest number which 9408 must be divided so that it becomes a perfect square. Also find the square root of the number so obtained.

Answers

Answered by dfgh4
22
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Answered by MelissaTan
8
It is impossible for 1 to be the smallest number as 9408 divided by 1 will still be 9408 so let's begin with 2.

9408 ÷ 2 = 4704
√4704 = 68.586

As the square root of the number obtained is 68.586, it means 2 is not the smallest number.

9408 ÷ 3 = 3136
√3136 = 56

Therefore 3 is the smallest number and 56 is the square root of the number obtained.
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