Math, asked by sannvi1964, 9 months ago

find the smallest number which divided by 7 12 18 and 21 case remainder 3 8 14 and 17 respectively​

Answers

Answered by abhishekanand4398
2

Answer:248

Step-by-step explanation:

7-3=4

12-8=4

18-14=4

21-17=4

Thus 4 is remainder in each case

Now,

L.C.M of 7 ,12,18and 21= 252

Required number =252-4=248

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