find the smallest number which divided by 7 12 18 and 21 case remainder 3 8 14 and 17 respectively
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Answer:248
Step-by-step explanation:
7-3=4
12-8=4
18-14=4
21-17=4
Thus 4 is remainder in each case
Now,
L.C.M of 7 ,12,18and 21= 252
Required number =252-4=248
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