Math, asked by ramsharao2045, 9 months ago

if x=1is a zero of the polynomial f(x)=x^3-2x^2+4x+k find value of k​

Answers

Answered by muanhoih
2

Answer:

x=1 is a zero of the polyno mial...

so,p(1)=0

1^3-2.1^2+4.1+k=0

1-2+4+k=0

3+k=0

k=-3

hehehelove to solve the math problem

Answered by Anonymous
1

Answer:

f(x) =  {x}^{3}  - 2x^{2} + 4x + k \\ f(1) =  {1}^{3}  - 2(1)^{2} + 4(1) + k \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 1 - 2(1) + 4(1) + k \\   \:  \:  \:  \:  \:  \:  \:  \: \:  \:  = 1 - 2 + 4 + k   \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = ( - 1) + 4 + k \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 3 + k \\  given \: that \: 1 \: is \: a \: zero \: of  \\ polynomial \: so \: f(1) = 0 \\

3 + k = 0 \\ k = ( - 3)

I hope it is helpful..........................

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