Question

find the smallest number which is divided by 15 24 32 and 45 gives remainder 8 17 25 and 38

Answer 1

Answer:

20=2*2*5

25=5*5

35=1*5*7

40=2*2*2*5

LCM of 20,25,35,40 =2*2*2*5*5*7 = 1400

The remainder is 6 less than the divisor in each of the cases

Hence the required number = LCM - 6 = (1400-6) = 1394

Answer 2

Answer:

the answer of the question os 428