find the smallest number which is divided by 5,6,7,8 remaining will 3 in each condition and when divided by 9 remaining will zero
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Step-by-step explanation:
1st LCM 5,6,7,8 is 840. and each case remaining will 3. So smallest number is 840+3 = 843.
843 is not divisible by 9. so, 840*2=1680. So required number is 1680+3=1683.
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