Find the smallest number which is divisible by 16 24 26 and 32 when it is increased by 5
Answers
Answered by
5
Answer:
2073.6
Step-by-step explanation:
this is the number which is divisible by 16,24,26, and 32 when it is increased by 5
Answered by
1
Step-by-step explanation:
First take out the LCM of the 16, 24, 32, 26.
Your answer is 1248.
I hope it will help
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