Find the smallest number which is divisible by 306 and 657
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Answer:
2 × 3² × 17 × 73 = 22338
Step-by-step explanation:
Prime factorizations are:
306 = 2 × 3² × 17
657 = 3² × 73
The required number is then the least common multiple (LCM) of 306 and 657. This will have just enough of each prime factor to be divisible by 306 and by 657. So...
LCM(306, 657) = 2 × 3² × 17 × 73 = 22338
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