Question

find the smallest number which is divisible by each of the numbers 6 9 and 15

Answer 1

Hey there!

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.

So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900

Answer 2

Take LCM...

6=2×3.

9=3×3

15=3×5

•°• 2×3×3×5

=90.

90 is divisible by

6 (15 times)

9 (10 times)

15 (6 times)