Question

find the smallest number which is exactly divisble by 12 20 and 40 after 24 is subtracted from it​

Answer 1

Answer:

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Step-by-step explanation:

Smallest number exactly divisible by 12,20,224 and 32 is their LCM.

Prime factorisation:

12 =2*2*3

20 =2*2*5

24=2*2*2*3

32=2*2*2*2*2

LCM is given by the product of prime factors, each raised by the highest exponent. As 2 occur maximum 5 times, 3 and 5 occur one time each.

LCM =2*2*2*2*2*3*5 =480

Hence, the required smallest number is 480.