Question

find the smallest number which is exactly divisible by 15 20 and 30

Answer 1

Answer:

hope it's help you

Step-by-step explanation:

15 = 3 * 5

20 = 2 * 2 * 5

30 = 2 * 3 * 5

two 2’s by one 3 by one 5 = 2 * 2 * 3 * 5 = 60 That is the answer

Answer 2

$\mathtt{\blue{\underline{\underbrace{ANSWER}}}}$

$\implies$ Factors of 15 = 3 , 5

$\implies$ Factors of 20 = 2 , 2 , 5

$\implies$ Factors of 30 = 2 , 3 , 5

$\therefore$ Common Factors of 15 , 20 , 30 are $\bullet \longrightarrow$

$\implies$ 2 × 2 × 3 × 5 = 60

$\therefore$ 60 is exactly divisible by 15 , 20 and 30

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Proof of the above calculations :-

$\implies$ division of 60 by 15 = $\rightarrow \frac{60}{15} \\ \\ \rightarrow \frac{20}{5} \\ \\ \rightarrow 4 \:✓$

$\implies$ division of 60 by 20 = $\rightarrow \frac{60}{20} \\ \\ \rightarrow \frac{30}{10} \\ \\ \rightarrow 3 \:✓$

$\implies$ division of 60 by 30 = $\rightarrow \frac{60}{30} \\ \\ \rightarrow \frac{30}{15} \\ \\ \rightarrow 2 \:✓$

$\therefore$ 60 is exactly divisible by 15 , 20 , 30

$\boxed{PROVED}$