Find the smallest number which is exactly divisible by 20, 32 and 36
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Answer:
take out HCF of 20,32,and 36
20=2×2×5
32=2×2×2×2×2
36=2×2×3×3
now,take common between the three
i.e.2×2
therefore,HCF=2×2
=4
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