Question

find the smallest number which leaves a remainder of 5 when divided by 24 32 and 42.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let the number be N so when divided by 24 32 and 42 it will always leaves remainder 5

Now first we find out the LCM of these number so that we can figure it out the least number.

24 32 and 42 have LCM comes out to be 672. But we said that the smallest that could be divisible by 5 So ( N + 5 ) is the number which is the smallest and leaves remainder 5.

So N + 5 = 672 + 5 = 677 is the smallest number which leaves remainder 5 when divided by 24 42 and 32.

[ Note :- Since N = LCM of Divisor + Remainder ]

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