Question

Find the smallest number which leaves remainders 8 and 12 when divided by 28 and 32
respectively
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Answer 1

Step-by-step explanation:

Given that the smallest no. When divided by 28 & 32 leaves remainder 8 & 12.

Therefore, 28–8=20 & 32–12=20 are divisible by the required number will be 20 less than the LCM of 28 and 32.

28= 2² x 7

32 = 2^5

So, LCM = 2^5 * 7 = 224

Therefore, 224–20=204…

Hence, the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 is 204…

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