Question

Find the smallest number which
leaves remainders 8 and 12 when
divided by 28 and 32 respectively.
​

Answer 1

HELLO DEAR FRIEND

GIVEN NUMBERS = 28 AND 32

GIVEN REMAINDERS = 8 AND 12

THE NUMBER WHICH WILL BE DIVISIBLE BY THE NUMBER.

= 28 - 8 = 20 AND 32 - 12 = 20

SO, 20 IS COMMON.

SO THE REQUIRED NUMBER

WILL BE

20 ans