Math, asked by veeruthrishul, 6 months ago

Find the smallest number which leaves the remainders 13, 41 and 29 at the end when dividedby 20, 48 and 36
respectively.

Answers

Answered by bhavyasodhani895

1

Answer:

Smallest such positive number is 720. But this number is after adding 7; so required number is 713.

Step-by-step explanation:

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