Question

find the smallest number which must be multiplied by 2028 so that we get a perfect square​

Answer 1

Answer:

we have to multiply it with 3.

2028×3=6084 which is the square of 78.

78^2=6084

I hope it is helpful

Answer 2

Firstly finding "Prime factorisation" of 2028

2028 = 2 × 2 × 3 × 13 × 13

As we see 2 and 3 are paired and 3 is unpaired. To make it a perfect square we have to multiply it by 3

When we multiply 2028 with 3. The product is 2028 × 3 = 6084

6084 is perfect square of 78

Hence the minimum number required to make 2028 a perfect square is "3"