Math, asked by aditya116334, 11 months ago

Find the smallest number which , on adding 19 to it , exactly divisible by 28, 36, and45​

Answers

Answered by Raggx0910
1

Answer:

Find the Least Common Multiple of 28, 36, and 45, then subtract 19 from their LCM.

LCM: 1,260 

1,260 - 19 = 1,241

ANSWER:  1,241

Check:

1,241 + 19 = 1,260

1,260 ÷ 28 = 45

1,241 + 19 = 1,260

1,260 ÷ 36 = 35

1,241 + 19 = 1,260

1,260 ÷ 45 = 28

Answered by roshdale2006
1

Answer:

1260

Step-by-step explanation:

     prime factorisation .........

       

   2     28 , 36 , 45

   2        14 , 18 , 45

   3           7 , 9 , 45

   3           7 , 3 , 15  

    7           7 ,  1 , 5

   5             1, 1 , 5

                  1, 1 , 1      

l.c.m = 2 x 2 x 3 x 3 x 7 x 5  = 1260

           

1260 - 19 = 1241

1260  /28 = 45

1260  / 36 = 35

1260  / 45 = 28

Hope it may help you..........!!

follow me pls......!!

Similar questions