Question

Find the smallest number which when added to 5 is exactly divisible by 12,14,18

Answer 1

Find the L.C.M of 12 , 14, 18
12 = 2^2 * 3
14 = 2*7
18 = 2*3^2
L.C.M = 2^2 * 3^2 * 7 = 252
252-5 = 247

Hence 247 is the smallest umber that should be added to 5 so that the resultant is exactly divisible by each of 12,14,18
Hope it helps.

Answer 2

Answer:

The required smallest number which when added to 5 is exactly divisible by 12,14,18 is 247.

Step-by-step explanation:

To find : The smallest number which when added to 5 is exactly divisible by 12,14,18 ?

Solution :

First we find the LCM of the numbers 12,14,18.

2 | 12   14    18

2 |  6    7     9

3 |  3    7     9

3 |  1     7     3

7 |  1     7     1

  |  1     1     1

$LCM(12,14,18)=2\times 2\times 3\times 3\times 7$

$LCM(12,14,18)=252$

Now, Subtract 5 from the number

$252-5=247$

Therefore, the required smallest number which when added to 5 is exactly divisible by 12,14,18 is 247.