find the smallest number which when divided by 1088, 640 and 100 leaves 3 as reminder in each case in
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Given:
find the smallest number which when divided by 1088, 640 and 100 leaves 3 as a reminder in each case.
To find:
The required number
Solution:
Prime factors of 1088:
1088 = 2x2x2x2x2x2x17 = 2⁶ x 17
Prime factors of 640:
640 = 2x2x2x2x2x2x2x5 = 2⁷ x 5
Prime factors of 100:
100 = 2x2x5x5 = 2² x 5²
LCM = 2⁷ x 5² x 17 = 128 x 25 x 17 = 54400
54400 + 3 = 54403
Hence, the required answer is 54403
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