Find the smallest number which when divided by 15 , 20 , 48 leaves [4]
9 as a remainder in each.
Answers
Answered by
1
Answer:
The answer is 249. 249 divided by 15 or 20 or 48 leaves a remainder of 9 in each case.
Answered by
18
Answer:
249
Step-by-step explanation:
- LCM(15,20,48)
- =240
- since remainder is 9 so adding 9 to 240
- 9+240=249.
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