Question

find the smallest number which when divided by 15 20 48 will each case leave 9 as the remainder​

Answer 1

Answer:

Step-by-step explanation:

LCM of 15,20,48 is 240

240+9 =249

It is because we have to find the smallest no. So the full formof LCM is lowest common factor ,so in smallest we will take Lcm and we will add 9

because in Lcm we add the remainder

Answer 2

The given question is we have to find the smallest number which when divided by 15 20 48 will each case leave 9 as the remainder

The number can be obtained by finding the LCM of these three numbers and add the number 9 to that LCM.

$15 = 5 \times 3 \\ 20 = 2 \times 2 \times 5 \\ 48 = 2 \times 2 \times 2 \times 2 \times 3$

The above are the factors of these numbers.

on taking the least common multiple.

The LCM will be

$5 \times 3 \times 2 \times 2 \times 2 \times 2 = 240$

On diving 240 with the above numbers we get the remainder 0,to get remainder as 9 add number 9 to the LCM we get

$240 + 9 = 249$

This is the final answer for the given question

# spj2

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