Math, asked by anup17899, 9 months ago

find the smallest number which when divided by 15,20,48 will in each case leave 9 as the reminder

Answers

Answered by raghuvanshiji

1

Answer:

Factors of

15 = 3x5

20 = 2x2x5

48 = 2x2x2x2x3

LCM = 2x2x2x2x3x5 = 240

240+9 = 249

The answer is 249.

249 divided by 15 or 20 or 48 leaves a remainder of 9 in each case.

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