Question

find the smallest number which when divided by 15,20,48 will in each case leave 9 as the reminder​

Answer 1

Answer:

249

Step-by-step explanation:

LCM(15,20,48)

=240

since remainder is 9 so adding 9 to 240

9+240=249.

Answer 2

The required number is 249.

Given:

The numbers are 15,20,48.

To Find:

We have to find the smallest number which when divided by 15,20,48 will in each case leave 9 as the reminder​.

Solution:

We know that the smallest number divided by 3 numbers a, b and c is the least common multiple of a,b and c.

Therefore, first, we have to find the LCM(15,20,48)

Now,

15=3×5

20=2×2×5

48=2×2×2×2×3

So, LCM(15,20,48)

=3×5×2×2×2×2

=240

Again, since the remainder is 9, so adding 9 to 240,

We get, 9+240=249.

Hence, the required number is 249.

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